What is the energy of a photon of red light with a frequency of 4.3 * 10^14 Hz?
What is the formula to calculate the energy of a photon? How can we determine the energy of a photon of red light with a frequency of 4.3 x 10^14 Hz?
The energy of a photon is determined by the equation E = hf, where E is the energy, h is Planck's constant (approximately 6.626 x 10^-34 J*s), and f is the frequency of the light. By substituting the given frequency of 4.3 x 10^14 Hz into the equation, we can calculate the energy of the photon as approximately 2.84 x 10^-19 Joules. This value represents the amount of energy carried by each individual photon of red light with the specified frequency.
Calculation of Photon Energy:
Where:
E = energy of the photon
h = Planck's constant (6.626 x 10^-34 J*s)
f = frequency of the light
Given:
Frequency (f) = 4.3 x 10^14 Hz
Planck's constant (h) = 6.626 x 10^-34 J*s
Substitute the values into the formula:
E = (6.626 x 10^-34 J*s) * (4.3 x 10^14 Hz)
E ≈ 2.84 x 10^-19 J
Therefore, the energy of a photon of red light with a frequency of 4.3 x 10^14 Hz is approximately 2.84 x 10^-19 Joules. This calculation demonstrates the energy content carried by each photon of red light with the specified frequency.