The Distance Traveled by a Movie Stunt Car off a Cliff

How far does the car travel during its fall?

Ignoring air resistance, how far does the car travel during its fall?

a) 20.2 m

b) 40.4 m

c) 60.6 m

d) 80.8 m

Final answer:

The car travels approximately 30.1 meters during its fall from the 44.1 m-high cliff with a horizontal speed of 10.0 m/s.

To find the distance traveled by the car during its fall, we can use the equation for the horizontal distance traveled by a projectile:

d = vx * t

Where d is the distance, vx is the horizontal velocity, and t is the time of flight.

Since the car is falling vertically, the time of flight can be determined by the equation:

t = sqrt((2 * h) / g)

Where h is the height of the cliff and g is the acceleration due to gravity.

Plugging in the values, we have:

t = sqrt((2 * 44.1) / 9.8) ≈ 3.01 s

Now we can find the horizontal distance:

d = 10.0 * 3.01 ≈ 30.1 m

So, the car travels approximately 30.1 meters during its fall.