a. What is the difference in the time the balls spend in the air?
b. What is the velocity of each ball as it strikes the ground?
c. How far apart are the balls 0.800 s after they are thrown?
a) The difference in the time the balls spend in the air is 3 seconds.
b) Each ball travels at a speed of 24.5 m/s as it lands.
c) The balls 0.800 s after they are thrown far apart are 23.52 meters.
Understanding Velocity:
Velocity: The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In principle, velocity is a vector quantity. It is the velocity where at distance changes. It is the migration change rate.
Detailed Explanation:
A) Calculating Time: We have initial velocity (u) = 14.7 m/s, acceleration (g) = 9.8 m/s², and the height of the balcony (s) = 19.6 m. By using the formula h = v o × t - g t² / 2, we can find the time taken for the first ball to hit the ground. Solving the equation, we get t = 1 second. The second ball takes 3 seconds to reach the ground. Therefore, the difference in time is 3 seconds.
B) Finding Velocity: The velocity of each ball as it strikes the ground can be calculated using the formula v = v o + g t, where v o is the initial velocity and t is the time taken. The first ball has a velocity of 24.5 m/s, and the second ball also has a velocity of 24.5 m/s.
C) Distance Calculation: To determine how far apart the balls are 0.800 seconds after they are thrown, we can use the formula d = v t + 0.5 a t², where d is the distance, v is the initial velocity, t is the time, and a is the acceleration due to gravity. The balls are 23.52 meters apart after 0.800 seconds.
For further information on velocity concepts and problem-solving techniques, you can explore resources like online educational platforms or seek help from knowledgeable sources in the field.