Let's Calculate Some Physics Fun!
What is the acceleration of an object that starts from rest and reaches a velocity of 6m/s after traveling 9m?
a) 1m/s^2
b) 2m/s^2
c) 3m/s^2
d) 4m/s^2
Answer:
The correct answer is b) 2m/s^2
To solve this question, we can use the kinematic equation:
vf^2 = vi^2 + 2ad
Where:
vf = final velocity (6m/s)
vi = initial velocity (0, as the object starts from rest)
d = distance traveled (9m)
a = acceleration (what we need to find)
Now, we can plug in the values and solve for acceleration:
6^2 = 0^2 + 2 * a * 9
36 = 18a
a = 36 / 18 = 2m/s^2
Therefore, the acceleration of the object is 2m/s^2 as it travels from rest to a velocity of 6m/s after covering a distance of 9m. Physics can be fun, right?