How many liters of water does a 2.0 hp electric motor pump in 1 hour?

What factors need to be considered to determine the number of liters of water pumped by a 2.0 hp electric motor in 1 hour?

The electric motor with a power of 2.0 hp pumps water from a depth of 10 m below the surface. To determine the number of liters of water pumped in 1 hour, we need to consider the power of the motor and the density of water.

Calculating the Volume of Water Pumped

Power Conversion: First, let's convert the power from horsepower (hp) to watts (W). 1 hp is approximately equal to 745.7 W. Therefore, the power of the motor is: P = 2.0 hp * 745.7 W/hp = 1491.4 W Volume Calculation: Next, we use the formula to calculate the volume of water pumped per second (Q): Q = P / (ρ * g * h) Where: P is the power in watts (1491.4 W), ρ is the density of water (1.0 kg/L or 1000 kg/m³), g is the acceleration due to gravity (approximately 9.8 m/s²), h is the height or depth the water is lifted (10 m). Substituting the values into the formula: Q = 1491.4 W / (1000 kg/m³ * 9.8 m/s² * 10 m) Q ≈ 0.152 m³/s Conversion to Liters: Since there are 1000 liters in 1 cubic meter, we convert the volume from cubic meters to liters: Q = 0.152 m³/s * 1000 L/m³ = 152 L/s Volume Pumped in 1 Hour: To find the volume of water pumped in 1 hour, we multiply the flow rate by the number of seconds in an hour: Volume pumped in 1 hour = 152 L/s * 3600 s = 547,200 L Therefore, the electric motor pumps approximately 547,200 liters of water in 1 hour.
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