How long will it take for a packet dropped from a ascending balloon to reach the ground?
What is the scenario described here and what are the key elements involved in finding the time for the packet to reach the ground?
Scenario Explanation:
Key Elements:
1. Initial Height: The balloon is at a height of 80m above the ground. 2. Rate of Ascent: The balloon is ascending at a rate of 9m/s. 3. Acceleration Due to Gravity: The acceleration due to gravity is approximately -9.81m/s^2. 4. Time to Reach Ground: The unknown variable we need to calculate. To find the time it takes for the packet to reach the ground when dropped from a balloon ascending at a rate of 9 m/s and at a height of 80m above the ground, we can use the following kinematic equation: h = ut + 1/2at^2 Where: - h is the height (negative since it's above the ground) - u is the initial velocity of the packet (negative since it's in the opposite direction of gravity) - a is the acceleration due to gravity - t is the time we want to find We can rearrange the equation and solve for t to determine that the packet will reach the ground in approximately 2.92 seconds.The packet will reach the ground in approximately 2.92 seconds when dropped from a balloon ascending at 9m/s from a height of 80m above the ground. Explanation: To find the time for the packet to reach the ground: h = ut + 1/2at^2 -80 = -9t + 1/2(-9.81)t^2 Solving for t, we get t ≈ 2.92 seconds. Therefore, it will take approximately 2.92 seconds for the packet to reach the ground when dropped from the balloon.