Escape Velocity Calculation in the Solar System
Calculate the Escape Velocity of the Solar System
Imagine we had an object at Earth's orbit (1.5x1011 m from the Sun). From this distance, what is the escape velocity of the Solar System? Recall that the Sun has a mass of 2x1030 kg.
Final Answer
The escape velocity from Earth's orbit in the Solar System is approximately 61745 m/s.
Explanation
The escape velocity of an object at a certain distance from the Sun can be calculated using the formula:
v = sqrt(2GM/r)
Where v is the escape velocity, G is the gravitational constant (6.67430 x 10-11 m3 kg-1 s-2), M is the mass of the Sun, and r is the distance from the Sun.
Plugging in the values, we have:
v = sqrt(2 x (6.67430 x 10^-11) x (2 x 10^30) / (1.5 x 10^11))
Simplifying the equation gives:
v ≈ 61745 m/s
Therefore, the escape velocity of the Solar System from Earth's orbit is approximately 61745 m/s.
Imagine we had an object at Earth's orbit (1.5x10^11 m from the Sun). From this distance, what is the escape velocity of the Solar System? Recall that the Sun has a mass of 2x10^30 kg. The escape velocity from Earth's orbit in the Solar System is approximately 61745 m/s. The calculation is based on the formula v = sqrt(2GM/r) where v is the escape velocity, G is the gravitational constant, M is the mass of the Sun, and r is the distance from the Sun. By substituting the values into the formula, we can determine the escape velocity of the Solar System.