Electrical Fuse Diameter Calculation Excitement!

What is the diameter of the wire in the fuse?

Calculate the diameter of the wire in the fuse where the current density is 620 a/cm2 and the current that causes the fuse to melt is 4.0 A.

Answer:

The diameter of the wire in the fuse is approximately 20.2 mm.

To solve for the diameter of the wire in the fuse, we can use the formula for current density:

Current density = current / (pi * (diameter/2)^2)

We know that the current density is 620 a/cm2 and the current that will cause the fuse to melt is 4.0 A. First, we need to convert the current density to the correct units.

Since the current is given in amps and the diameter is given in cm, we need to convert the current density to A/cm2:

620 a/cm2 = 0.062 A/mm2

Now we can substitute the values into the formula and solve for the diameter:

0.062 A/mm2 = 4.0 A / (pi * (diameter/2)^2)

Simplifying:

(diameter/2)^2 = 4.0 A / (pi * 0.062 A/mm2)

(diameter/2)^2 = 102.04 mm2

diameter/2 = sqrt(102.04 mm2)

diameter/2 = 10.1 mm

diameter = 20.2 mm

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