Camel's Journey to Oasis B
Imagining a Cartesian coordinate plane, let's place oasis A at point (0,0) and oasis B at point (25,0).
The camel first walks 24 km in a direction 20° south of east. This can be broken down into x and y components:
x = 24 * cos(20°) ≈ 22.55 km
y = 24 * sin(20°) ≈ -8.21 km
After this leg of the journey, the camel's position is at approximately (22.55, -8.21).
Next, the camel walks 7.0 km due north, which increases its y-coordinate:
new y-coordinate = -8.21 + 7 = -1.21 km
Now, to find the distance from the camel's current position to oasis B:
D = √((25 - 22.55)² + (-1.21 - 0)²) = 2.73 km
Therefore, the camel is approximately 2.73 km away from oasis B after its journey.