Calculating the Speed of the Bundle Thrown Upwards

How fast did a person throw a small bundle toward their friend on a balcony 10 meters above them?

The speed with which they threw the bundle is 14 m/s.

Understanding the Speed Calculation Process

To calculate the speed of the bundle thrown upwards, we can utilize the equations of kinematics. When an object is thrown upwards, it undergoes a motion influenced by gravity. In this scenario, a person threw a small bundle towards their friend on a balcony located 10 meters above them. The initial speed at which the bundle was thrown is provided at 14 m/s. Using the equations of motion, we can determine the final velocity of the bundle thrown upwards by taking into account the acceleration due to gravity and the height of the balcony. The equation for upward motion under gravity is: v^2 = u^2 - 2gh Where: v = final velocity u = initial velocity g = acceleration due to gravity (approx. 9.8 m/s^2) h = height (10 meters in this case) At the maximum height, the final velocity (v) of the bundle will be 0 m/s. Substituting the given values into the equation, we can solve for the initial velocity (u) of the bundle. Calculating u: u^2 = 2gh u = √(2gh) u = √(2 * 9.8 * 10) u = 14 m/s Therefore, the speed at which the bundle was thrown upwards is also 14 m/s.
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