Calculating the Resistance of a Light Bulb
Understanding the Power Rating of Light Bulbs
A common way to describe the power of a light bulb is by using its power rating, such as a 100W bulb. The power rating indicates the amount of power the light bulb dissipates when connected across a specified potential difference.
The Question:
What is the resistance of a 100W light bulb connected to a 120V potential difference?
light bulbs. the power rating of a light bulb (such as a 100 w bulb) is the power it dissipates when connected across a 120 v potential difference. what is the resistance of a 100 w bulbFinal answer:
The resistance of a 100W light bulb connected to a 120V potential difference is approximately 14.4 ohms.
Explanation:
The power rating of a light bulb represents the power it dissipates when connected across a certain potential difference. In this case, a 100W bulb is connected to a 120V potential difference.
To find the resistance of the bulb, we can use Ohm's Law which states that resistance (R) is equal to the voltage (V) divided by the current (I), meaning R = V/I.
Since power (P) is the product of voltage (V) and current (I), we have P = V * I. Rearranging this equation, we can solve for current: I = P/V.
Therefore, the resistance (R) of the light bulb can be calculated by dividing the potential difference (V) by the current (I): R = V/I = V/(P/V) = V^2/P.
In this case, the resistance (R) of a 100W light bulb connected across a 120V potential difference would be approximately 14.4 ohms.