A car starts from rest and accelerates uniformly

Acceleration of a Car

A car starts from rest and accelerates uniformly over a time of 5.37 seconds for a distance of 101 m. We need to determine the acceleration of the car.

Given data:

Time taken (t) = 5.37 seconds

Distance covered (d) = 101 m

Initial velocity (u) = 0 m/s

Formula:

Acceleration (a) can be calculated using the formula:

a = 2 * (d - ut) / t^2

Calculation:

Substitute the given values into the formula:

a = 2 * (101 m - 0 m/s * 5.37 s) / (5.37 s)^2

a = 2 * 101 m / (5.37 s)^2

a = 202 m / 28.77 s^2

a ≈ 8.10 m/s^2

Answer:

8.10 m/s^2

Explanation:

Therefore, the acceleration of the car is 8.10 m/s^2.

What is the acceleration of the car if it starts from rest and accelerates uniformly over a time of 5.37 seconds for a distance of 101 m? The acceleration of the car is 8.10 m/s^2.
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