What is the proper position for the Seated Barbell Triceps Extension exercise?

Calculating the Moment of Inertia

The torque equation: τ = Iα

Given values: Force (F) = 2.00 × 10³ N, Lever arm distance (r) = 0.03 m, Angular acceleration (α) = 120 rad/s²

The question asks to calculate the moment of inertia of a boxer's forearm using the information provided about the force exerted by the triceps muscle and the resulting angular acceleration. To find the moment of inertia, we can use the equation τ = Iα, where τ is the torque, I is the moment of inertia, and α is the angular acceleration.

The torque (τ) can be calculated by multiplying the force exerted by the muscle (F) by the effective perpendicular lever arm distance (r), which gives τ = F × r. Given that F = 2.00 × 10³ N and r = 0.03 m, the torque is calculated as τ = (2.00 × 10³ N) × (0.03 m) = 60 N·m.

With the angular acceleration (α) given as 120 rad/s², we can rearrange the torque equation to solve for the moment of inertia: I = τ/α. Plugging in the values gives us I = 60 N·m / 120 rad/s², resulting in a moment of inertia of 0.5 kg·m² for the boxer's forearm.