Determining Synchronous Speed of an AC Motor
What is the synchronous speed of a 2-pole, 60-hertz AC motor?
Answer:
The synchronous speed of a 2-pole, 60-hertz AC motor is 3600 RPM.
The synchronous speed of an AC motor is an important parameter to understand in the field of electrical engineering. In this case, for a 2-pole, 60-hertz AC motor, the synchronous speed is calculated as 3600 RPM.
Explanation:
To determine the synchronous speed of a 2-pole, 60-hertz AC motor, we use the formula:
Synchronous speed (in RPM) = (120 * frequency) / number of poles
Given that the motor has 2 poles and operates at a frequency of 60 hertz, we can substitute these values into the formula:
Synchronous speed (in RPM) = (120 * 60) / 2 = 3600 RPM
Therefore, the synchronous speed of the 2-pole, 60-hertz AC motor is 3600 RPM. This value represents the rotational speed at which the magnetic field of the stator rotates in sync with the rotor.