Data Allocation and Sequence of an Array

What is the number of bytes allocated to the array club?

What is the address of the third element if the array club is stored column-wise?

What is the sequence of data if the elements are stored column-wise?

1. The number of bytes allocated to the array club is 24 bytes.

2. The address of the third element, assuming club is stored column-wise and the address of club is at 6700001, would be 6700025.

3. The sequence of data if the elements are stored column-wise is 70, 39, 62, 35, 30, 29.

In order to determine the number of bytes allocated to the array club, we need to consider the size of each element in the array. Since the array is declared as int, each element takes up 4 bytes. By multiplying the number of rows (NUMFAMILY) by the number of columns (NUMMEMBERS) and then multiplying the result by 4 (size of each int element), we get a total of 24 bytes allocated to the array club.

When the array club is stored column-wise and the address of the club is at 6700001, we calculate the address of the third element by considering the size of each element and the number of elements before it. Each int element takes up 4 bytes, and there are 2 elements before the third element in a column-wise storage. Therefore, the address of the third element is 6700001 + (2 * 3 * 4) = 6700025.

If the elements are stored column-wise, the sequence of data would be 70, 39, 62, 35, 30, 29. This means that the elements are stored in a column-wise fashion where the first column is stored consecutively followed by the second column.