What volume will 3.50 mol of ammonia gas occupy at conditions of standard temperature pressure?

Calculation of Volume of Ammonia Gas

When given the quantity of a gas in moles, it is possible to calculate the volume of the gas by using the Ideal Gas Law equation:

PV = nRT

Where:

P = Pressure

V = Volume

n = Number of moles

R = Ideal Gas Constant

T = Temperature

Given:

Number of moles (n) = 3.50 mol

Standard Temperature (T) = 273 K

Standard Pressure (P) = 1 atm

Ideal Gas Constant (R) = 0.0821 L•atm/mol•K

Let's substitute the given values into the Ideal Gas Law equation:

1 atm * V = 3.50 mol * 0.0821 L•atm/mol•K * 273 K

V = (3.50 * 0.0821 * 273) / 1

V = 78.4 L

Therefore, the volume that 3.50 mol of ammonia gas will occupy at conditions of standard temperature pressure is 78.4 liters.