The Volume of Ammonia Gas at Standard Temperature and Pressure
What volume will 3.50 mol of ammonia gas occupy at conditions of standard temperature and pressure?
Answer:
Q: What volume will 3.50 mol of Xe gas occupy at STP?
A: 78.4 L
Explanation:
The volume occupied by 3.5 moles of ammonia gas at standard temperature and pressure (STP) is 78.45 L
Data obtained from the question
- Number of moles (n) = 3.5 moles
- Pressure (P) = STP = 1 atm
- Temperature (T) = STP = 273 K
- Gas constant (R) = 0.0821 atm.L/Kmol
- Volume (V) = ?
How to determine the volume
The volume of the gas at standard temperature and pressure (STP) can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
1 x V = 3.5 x 0.0821 x 273
V = 78.45 L
When solving for the volume of gas at standard temperature and pressure (STP), it is important to consider the number of moles, pressure, temperature, and gas constant involved in the ideal gas equation. In this case, we are given 3.5 moles of ammonia gas at STP.
By utilizing the ideal gas equation PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature, we can calculate the volume of the gas.
Plugging in the values for pressure (1 atm), number of moles (3.5), gas constant (0.0821 atm.L/Kmol), and temperature (273 K), we can determine that the volume of 3.5 moles of ammonia gas at STP is 78.45 L.
This calculation demonstrates how the ideal gas equation can be applied to find the volume of a gas under specific conditions such as standard temperature and pressure.