The Chemistry Questions You Need Answered!

Question 1:

What is the mass of NaHCO3 required to produce 224L of CO2 at STP?

Answer:

The mass of NaHCO3 required to produce 224L of CO2 at STP is 840 grams.

Explanation:

To calculate the mass of NaHCO3 required to produce 224L of CO2 at STP, we can use the stoichiometry of the balanced equation and the molar volume of gases at STP. From the balanced equation, we can see that 1 mole of NaHCO3 produces 1 mole of CO2. Therefore, the number of moles of CO2 produced can be calculated using the molar volume of gases at STP: 1 mole of any gas occupies 22.4 liters at STP.

So, the number of moles of CO2 produced is: 224L CO2 * (1 mole CO2 / 22.4L CO2) = 10 moles CO2. Since the balanced equation tells us that 1 mole of NaHCO3 produces 1 mole of CO2, the number of moles of NaHCO3 required is also 10 moles.

The molar mass of NaHCO3 is 84 g/mol, so the mass of NaHCO3 required is: 10 moles NaHCO3 * 84 g/mol = 840 g NaHCO3.