Specific Heat Capacity of Ice Calculation

What is the specific heat capacity of ice in units of J/g⋅°C?

How can we calculate the specific heat capacity of ice?

Specific Heat Capacity of Ice Calculation:

The specific heat capacity of ice can be calculated using the formula:

q = m * c * ΔT

To calculate the specific heat capacity of ice, we first need to determine the amount of heat absorbed, the mass of ice, and the change in temperature.

Given that 6.80 g of ice absorbs 0.149 kJ of heat and the temperature changes from 0.0 °C to 10.5 °C:

First, calculate the mass of the ice:

density = mass / volume

mass = density * volume = 0.917 g/cm³ * (6.80 g / 0.917 g/cm³) = 50 g

Next, calculate the change in temperature:

ΔT = 10.5 °C - 0.0 °C = 10.5 °C

Then, plug in the values for q, m, and ΔT to solve for c:

c = q / (m * ΔT) = 0.149 kJ / (50 g * 10.5 °C) = 0.283 J/g⋅°C

Therefore, the specific heat capacity of ice is 0.283 J/g⋅°C.