Molarity Calculation for Phosphoric Acid Solution
What is the molarity of phosphoric acid in a solution labelled 20% of Phosphoric acid by weight and a density of 1.12g/mL?
What is the definition of molarity in chemistry?
How do you calculate the number of moles of solute in a solution?
The molarity of phosphoric acid in a solution labelled 20% of Phosphoric acid by weight and a density of 1.12g/mL is 11.85 mol/L.
Molarity is the concentration unit in chemistry measured in moles per liter (mol/L).
Molarity is an important concept in chemistry that helps to quantify the concentration of a solution. In this case, we are calculating the molarity of phosphoric acid in a solution that is labeled as 20% phosphoric acid by weight and has a density of 1.12g/mL.
The first step in calculating the molarity is to determine the number of moles of phosphoric acid in the solution. We can do this by using the formula:
Number of moles = Mass / Molar mass
Given that the mass is 20% of the solution and the molar mass of phosphoric acid is 98:
Number of moles = 20 / 98 = 0.204 moles
Next, we need to calculate the volume of the solution using the density:
Volume = Mass / Density
Volume = 20 / 1.12 = 17.85 ml
Now, we can calculate the molarity using the formula:
Molarity (M) = Number of moles / Volume
Plugging in the values we have:
M = 0.204 / 17.85 * 1000 / 1 = 11.85 mol/L
Therefore, the molarity of phosphoric acid in the solution is 11.85 mol/L.