Galena Extraction Process: Mass of Galena Converted to Lead (II) Oxide

a. Write a balanced equation for the reaction.
b. What mass of galena is converted to lead (II) oxide if 975 kJ of heat is produced?

a. The balanced equation for the reaction can be written as follows:
2 PbS + 3 O2 -> 2 PbO + 2 SO2
b. To determine the mass of galena (PbS) converted to lead (II) oxide (PbO), we need to use the stoichiometry of the balanced equation.
From the balanced equation, we can see that 2 moles of PbS react to produce 2 moles of PbO. This means that the molar ratio between PbS and PbO is 1:1.
Therefore, if 975 kJ of heat is produced, the mass of galena (PbS) converted to lead (II) oxide (PbO) is 239.3 grams.

Calculating the Mass of Galena Converted to Lead (II) Oxide

To calculate the mass of PbS, we need the molar mass of PbS, which is the sum of the atomic masses of lead (Pb) and sulfur (S). The atomic masses of Pb and S are approximately 207.2 g/mol and 32.1 g/mol, respectively.
Molar mass of PbS = 207.2 g/mol + 32.1 g/mol = 239.3 g/mol
Now, we can set up a proportion to find the mass of PbS:
(239.3 g PbS / 2 mol PbS) = (x g PbO / 2 mol PbO)
Solving for x, the mass of PbO produced, we can find:
x = (239.3 g PbS * 2 mol PbO) / 2 mol PbS = 239.3 g PbO
Therefore, if 975 kJ of heat is produced, the mass of galena (PbS) converted to lead (II) oxide (PbO) is 239.3 grams.
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