Chemical Stoichiometry: Volume Calculation Example
How do we determine the volume of 1.5 M NaOH needed to react completely with 448 mL of 0.600 M HCl?
a. 180 mL
b. 1100 mL
c. 0.18 mL
d. 448 mL
Final answer:
Answer:
To determine the volume of 1.5 M NaOH needed to react completely with 448 mL of 0.600 M HCl, we can use the concept of stoichiometry. The correct answer is option c. 0.18 mL.
Explanation:
To determine the volume of 1.5 M NaOH needed to react completely with 448 mL of 0.600 M HCl, we can use the concept of stoichiometry. From the balanced chemical equation:
NaOH + HCl → NaCl + H2O
We can see that the mole ratio between NaOH and HCl is 1:1. Therefore, the number of moles of HCl is equal to the number of moles of NaOH. To find the number of moles of HCl, we use the equation:
Moles = Molarity x Volume (in liters)
Given that the volume of HCl is 448 mL (or 0.448 L) and the molarity is 0.600 M, we can solve for the number of moles of HCl:
Moles HCl = 0.600 M x 0.448 L = 0.2688 mol HCl
Since the mole ratio between NaOH and HCl is 1:1, the number of moles of NaOH needed is also 0.2688 mol NaOH. Now, we can use the molarity of NaOH to find the volume:
Given that the molarity of NaOH is 1.5 M, we can use the equation:
Volume = Moles / Molarity
Substituting the values, we get:
Volume NaOH = 0.2688 mol / 1.5 M = 0.1792 L = 179.2 mL
Therefore, the correct answer is option c. 0.18 mL.